CARE Tour
Before the tower every day, fat is required. , Then in bed, or a waste piece of cloth to remove excess fat and the time required would have laid all the chips at the end of the tower was working. All vehicles will be wiped clean and replace them. All vehicles must be kept sharp at all times.
SPEED Tour
Signal to the 2400-3000 revolutions per minute, will change, when conical pulley and small stage band. If this stock speeds up to around 3 "can be activated with any certainty. Stock" diameter 3 "must have been hit for 6 from the second or third, all the shares of more than 6" the last step. To speed depends entirely on the type of work and material usage, run with a rotation. As full-centric and rough edges can not be stuck with all work slowly, and inventories should be taken off the corners should be made. This piece is very high centrifugal forces, high speeds, cause the tower to vibrate, and part at casting is possible, and by return of risks to workers in these environments. Then you can run stock speeds should increase.
Lathe Speed
A general rule is the larger the piece (diameter or length) the slower RPM. In addition, a slower speed will be safer when working with unbalanced pieces until you have turned the piece basically round.
These tables provide a starting point or comparison between size and speed.
Spindle work Speeds |
|
Units : RPM |
Facework Speeds |
Depth | |||
Diameters | 2" (50mm) | 3" (75mm) | 4" (100mm) |
8" (205mm) | 1250 | 1250 | 1000 |
10" (255mm) | 1250 | 1000 | 900 |
12" (305mm) | 1250 | 1000 | 900 |
14" (355mm) | 1000 | 900 | 850 |
16" (405mm) | 750 | 650 | 600 |
18" (460mm) | 650 | 500 | 400 |
Units : RPM |
For older lathes:
TO FIGURE THE DIAMETER OF PULLEYS
Suppose a motor runs at 1500 RPM. and is fitted with a 4” pulley. Suppose also, a main shaft should run 300 R. P. M.
Then, 1500 : 300 :: x : 4; (that is : 1500RPM is to 300RPM as x is to 4)
You can write this as 1500/300 = x/4
or, rearrange to 300 * x = 4 * 1500 and then 300x = 6000. Divide both sides by 300 which gives x = 20; the diameter of the large pulley on the main shaft.
Suppose again that a line shaft runs 300 RPM, and a counter shaft 600 RPM. The counter shaft has a pulley 4" in diameter. The pulley on the line shaft must then have a diameter of 8”.
300 : 600 :: 4 : x;
Or, 300x = 2400, x =8”
Suppose the cone pulley on the counter shaft runs 600 RPM; a lathe spindle runs 2200 RPM, when connected with the small cone pulley which has a diameter of 3". The large cone pulley has then a diameter of 11”.
600 : 2200 :: 3 : x
Or, 600x = 6600; x = 11”
RULES FOR FINDING THE SPEEDS AND SIZES OF PULLEYS
1. To find the diameter of the driving pulley:
Multiply the diameter of the driven by the number of revolutions it should make and divide the product by the number of revolutions of the driver. (20 x 300 = 6000; 6000 / 1500 = 4+ - diameter of motor pulley.)
2. To find the diameter of the driven pulley:
Multiply the diameter of the driver by its number of revolutions and divide the product by the number of revolutions of the driven. (4 x 1500 = 6000; 6000 / 300 = 20”-diameter of the driven pulley.)
3. To find the number of revolutions of the driven pulley:
Multiply the diameter of the driver by its number of revolutions and divide by the diameter of the driven. (4 x 1500 = 6000; 6000 / 20 = 300 - revolutions of driven pulley.)
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